How does the capacitance of the capacitor influence the time required for the multivibrator, before it falls back to a stable state?

Take a look at the circuit shown.
You have replaced the capacitor **C1**
by a capacitor with a **capacity of 10 μF**.

Now the multivibrator switches to a much **shorter** time period
back into the **stable state**.

In fact, you can calculate the **switching time T**...

T = R_{2}C_{1} × 0.693

Now you can place the values...

T = 100,000 Ω × 0.00001 F × 0.693 = ca. 0.7 sec.

(Want to know where this formula comes from?
See **experiment 25**.)

Contrast this with the switching time **T**
from the **experiment 5**
(capacitor **C1 = 100 uF**)...

T = 100,000 Ω × 0.00010 F × 0.693 = ca. 7 sec.

From the formula
you can see that also the resistor **R2**
influences the switching time.
However, you are not free to choose any resistance.
This you investigate in experiment 26.

Now you discuss the third and last multivibrator...