What is the total capacity of a series circuit with two capacitors of different capacity? Just try it out....

Replace the capacitor **C2** from the last experiment by a
**10 μF capacitor**

The LEDs light up a **little shorter**
than what you expect from a
**10 μF** capacitor.
And indeed, you calculate the total capacity as...

C_{total} = ( C_{1} * C_{2} ) / ( C_{1} + C_{2} )
= ( 100 μF * 10 μF ) /
( 100 μF + 10 μF )
= 9 μF

The total capacity of a series circuit is **always smaller**
than the **smallest capacity** in the circuit.
If you replace the capacitor C2 by the **47 nF** ceramic capacitor,
you get a total capacity of **slightly less** than **47 nF**.

If you want to understand the reasons,
you should have a look at the **topic capacitor** in **physics**.

But first, enough is said about the properties of capacitors. In the following experiments you see where and how capacitors are used.