In the circuit shown you have three LEDs arranged in a series circuit. This has consequences for the current-limiting resistor, which you need to recalculate ...
Rv = ( U0 - 3 × ULED ) ÷ I
= ( 9 V - 3 × 2.0 V ) ÷ 0.015 A
= 200 Ω
The next highest resistor standard value is 220 Ω.
All three LEDs are lit, the power consumed is the same as for a single LED!
However also a series circuit of LEDs has restrictions...