In the Experiment 2 you found that with a current of Iout = 0.5 A not only the load restistor, but also the voltage regulator heat up significantly.
This is not a threat to the voltage regulator 78xx since it has an overheating protection and shuts down. However, this can cause all sorts of problems with your circuit when a voltage regulator to shut down unexpectedly. You should understand how the heat is generated and how to take care of it.
![]() Circuit diagram heat generation voltage regulator 7805. |
![]() Circuit heat generation voltage regulator 7805. (Enlarge) |
The power dissipation PD of the 78xx, and thus the generation of heat, is given by the formula...
PD = (Uin - Uout) × Iout + Uin × IGND
You can neglect the part (Uin × IGND) as IGND is only a few μA. Therefore, the calculated power dissipation... PD = (Uin - Uout) × Iout. = (9.0 V - 5.0 V) × 0.50A = 2.0 Watt. The resulting heat must be dissipated and you might need a heat sink to dissipate enough heat, for the voltage regulator to remain functional. However, you can also try to limit the power dissipation... |
![]() Heat sink with voltage regulator 78xx (TO220-casing). (Enlarge) |